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Q.

Two sources of emf 6 V and internal resistance 3 Ω and 2 Ω are connected to an external resistance R as shown. If potential difference across battery A is zero, then value of R is

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a

1  Ω

b

2  Ω

c

3  Ω

d

4  Ω

answer is A.

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Detailed Solution

I = 125+R ; V =−Ir=06−125+R×3=0 ⇒  R=1 Ω
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