First slide

Ohm's law

Question

Two sources of emf 6 V and internal resistance $3 Ω$ and $2 Ω$ are connected to an external resistance R as shown. If potential difference across battery A is zero, then value of R is

Moderate

A

$1 Ω$
B

$2 Ω$
C

$3 Ω$
D

$4 Ω$

Solution

$\begin{array}{l} I = \frac{12}{5 + R}; V = - Ir = 0 \\ 6 - (\frac{12}{5 + R}) \times 3 = 0 \Rightarrow R = 1 Ω \end{array}$

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