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Questions  

Two sources of emf 6 V and internal resistance 3Ω and 2Ω are connected to an external resistance R as shown. If potential difference across battery A is zero, then value of R is

a
1  Ω
b
2  Ω
c
3  Ω
d
4  Ω

detailed solution

Correct option is A

I = 125+R ; V =−Ir=06−125+R×3=0 ⇒  R=1 Ω

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