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'Two sources of equal e.m.f, are connected to an external resistance .R. The internal resistances of the two sources are R1, and R2 (R2 >R1) If the potential difference across the source having internal resistance .R2, is zero, then

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a

R = R2 - R1,

b

R=R1R2R2−R1

c

R=R1R2R1+R2

d

R=R2R1+R2R2−R1

answer is A.

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Detailed Solution

The current flowing through the circuit is given byi=2ER+R1+R2Potential difference across the source of internal resistance R2 is given byGIVEN v2=E-iR2=0E=2ER2R+R1+R2or R+R1+R2=2R2 or R=R2−R1

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