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Q.

Two sources of sound A and B produces the wave of 350 Hz, they vibrate in the same phase. The particle P is vibrating under the influence of these two waves, if the amplitudes at the point P produced by the two waves is 0.3 mm and 0.4 mm, then the resultant amplitude of the point P will be when AP – BP = 25 cm and the velocity of sound is 350 m/sec

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a

0.7 mm

b

0.1 mm

c

0.2 mm

d

0.5 mm

answer is D.

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Detailed Solution

λ=vn=350350=1 m=100cmAlso path difference (Δx) between the waves at the point of observation is AP−BP=25cm.   Hence ⇒Δφ=2πλ(Δx)=2π1×25100=π2⇒A=(a1)2+(a2)2=(0.3)2+(0.4)2=0.5mm
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Two sources of sound A and B produces the wave of 350 Hz, they vibrate in the same phase. The particle P is vibrating under the influence of these two waves, if the amplitudes at the point P produced by the two waves is 0.3 mm and 0.4 mm, then the resultant amplitude of the point P will be when AP – BP = 25 cm and the velocity of sound is 350 m/sec