Two sources of sound A and B produces the wave of $$350$$ Hz, they vibrate in the same phase. The particle P is vibrating under the influence of these two waves, if the amplitudes at the point P produced by the two waves is $$0.3$$ mm and $$0.4$$ mm, then the resultant amplitude of the point P will be when AP – BP $$=$$ $$25$$ cm and the velocity of sound is $$350$$ $$m/$$$$sec$$

Question

Infinity Learn · Accepted Answer

λ$$=vn=350350=1$$ $$m=100cmAlso$$ path difference $$($$Δ$$x)$$ between the waves at the point of observation is AP−$$BP=25cm$$.   Hence ⇒Δφ$$=2$$πλ$$($$Δ$$x)=2$$$$π$$$$1$$×$$25100=$$π$$2$$⇒$$A=(a1)2+(a2)2=(0.3)2+(0.4)2=0.5mm$$

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