Two spheres A and B of masses m1 and m2 respectively collide. A is at rest initially and B is moving with velocity v along X-axis. After collision, B has a velocity v/2 in a direction perpendicular to the original direction. The mass A moves after collision in the direction
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
same as that of B
b
opposite to that of B
c
θ = tan-112 to the X-axis
d
θ = tan-1-12to the X-axis
answer is C.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Initial momentum, pi=m2vi^ + m1×0Final momentum, pf=m2(v/2)j^ + m1×v1From law of conservation of momentum, pi=pf m2vi^=m2v2j^+m1×v1 v1=m2m1vi^-m2m1v2j^From this equation, we can find, tanθ=12⇒ θ = tan-112 to the X-axis.