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Two spheres A and B of radius 4 cm and 6 cm are given charges of 80 $μ$ C and 40 $μ$ C respectively. If they are connected by a fine wire, the amount of charge flowing from one to the other is

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20 μC from A to B

16 μC from A to B

32 μC from B to A

32 μC from A to B.

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detailed solution

Correct option is D

Total charge Q = 80 + 40 = 120 μC. By using the formula Q1′=Qr1r1+r2 New charge on sphere A is QA′=QrArA+rB=12044+6=48 μC. Initially it was 80 μC i.e., 32 μC charge flows from A to B.

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