Q.

Two spheres A and B of radius 4 cm and 6 cm are given charges of 80 μC and 40 μC respectively. If they are connected by a fine wire, the amount of charge flowing from one to the other is

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a

20 μC from A to B

b

16 μC from A to B

c

32 μC from B to A

d

32 μC from A to B.

answer is D.

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Detailed Solution

Total charge Q = 80 + 40 = 120 μC. By using the formula Q1′=Qr1r1+r2 New charge on sphere A is QA′=QrArA+rB=12044+6=48 μC. Initially it was 80 μC i.e., 32 μC charge flows from A to B.
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