Questions

Two spheres of radius a and b are charged and joined by a wire. The ratio of electric fields due to spheres of radius a and b is

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a/b

b/a

a2/b2

b2/a

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detailed solution

Correct option is B

Joined by a wire means they are at the same potential.For same potential kQ1a1=kQ2a2⇒Q1Q2=ab . Further, the electric field at the surface of the sphere having radius R and charge Q is kQR2.∴E1E2=kQ1/a2kQ2/b2=Q1Q2×b2a2=ba

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Two spherical shells are as shown in figure.

Let r be the distance of a point from their common centre. Then, match the following columns and mark the correct choice from the given codes.

	Column-I		Column-II
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