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Q.

Two spheres of radius a and b respectively are charged and joined by a wire. The ratio of electric field of the spheres is

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a

a/b

b

b/a

c

a2/b2

d

b2/a2

answer is B.

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Detailed Solution

Joined by a wire means they are at the same potential. For same potential kQ1a1=kQ2a2⇒Q1Q2=abFurther, the electric field at the surface of the sphere having radius R and charge Q is kQR2.∴E1E2=kQ1/a2kQ2/b2=Q1Q2×b2a2=ba
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