Questions
Two spheres of the same material have radii 1 m and 4 m and temperature 4000 K and 2000 K respectively. The energy radiated per second by the first sphere is
detailed solution
Correct option is C
The energy radiated per second, P, by a body of surface area A, at temperature T kelvin, is given by E = eσAT4Hence, E1 = eσ4π(1)2 × (4000)4 = eσπ×1024×1012 Jand E2 = eσ[4π(4)2](2000)4 = eσπ×1024×1012JSo, E1 = E2Similar Questions
For a black body at temperature 727°C, its radiating power is 60W and temperature of surrounding is 227° C. If temperature of black body is changed to 1227°C, then its
radiating power will be :
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