Questions
Two spherical bodies of the mass M and 5M and radii R and 2R respectively are released in free space with initial separation between their centres equal to 12 R. If they attract each other due to gravitational force only, then the distance covered by the smaller body just before collision is
detailed solution
Correct option is C
Let the collision takes place at a point O. Suppose the smaller sphere moves to a distance x. Now the bigger mass moves to a distance (9R - x). ThereforeF=GM×5M(12R−x)2Now asmall =FM=G×5M(12R−x)2abig=F5M=G×M(12R−x)2∴ x=12⋅asmall ⋅t2=12⋅G⋅M(12R−x)2⋅t2………….(1)and (9R−x)=12⋅abig ⋅t2=12⋅G⋅M(12R−x)2⋅t2…….(2)Dividing eq. (1) by eq. (2), we getX(9R−x)=5 or X=45R−5XSolving we get, x=7⋅5RTalk to our academic expert!
Similar Questions
When a projectile attains the escape velocity, then on surface of planet its
799 666 8865
support@infinitylearn.com
6th Floor, NCC Building, Durgamma Cheruvu Road, Vittal Rao Nagar, HITEC City, Hyderabad, Telangana 500081.
JEE Mock Tests
JEE study guide
JEE Revision Notes
JEE Important Questions
JEE Sample Papers
JEE Previous Year's Papers
NEET previous year’s papers
NEET important questions
NEET sample papers
NEET revision notes
NEET study guide
NEET mock tests