Two spherical soap bubbles of radii r1 and r2 in vacuum coalesce under isothermal condition. The resulting bubble has a radius R such that

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R = r1 +r2

R = (r1+r2)12

R = r12+r22

R = [(r1r2(r1+r2))]

answer is C.

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Detailed Solution

2×4πR2σ = 2×4πr21σ+2×4πr22σor R2 = r12+r22 or R = r12+r22

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