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Q.

Two springs are made to oscillate simple harmonically due to the same mass individually. The time periods obtained are T1 and T2. If both the springs are connected in series and then made to oscillate by the same mass, the resulting time period will be

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a

T1+ T2

b

T1T2T1+T2

c

T12+T22

d

T1+T22

answer is C.

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Detailed Solution

Let spring constant of two springs are K1 and K2, respec­tively, thenT1=2πmk1and T2=2πmk2k1=4π2mT12and k2=4π2mT22so when two springs are connected in series T=2πmkeqwhere keq=k1k2k1+k2Hence T=T12+T22
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