First slide

Work done by Diff type of forces

Question

Two springs A and B have force constants k_A and K_B, respectively, with k_A > K_B. Both springs are stretched by the same force, then the work done is :

Easy

A

same in both cases
B

greater in case of spring A
C

smaller in case of spring A
D

none of the above

Solution

Work done by spring force $= \frac{1}{2} {kx}^{2} = \frac{(kx)^{2}}{2 k} = \frac{F^{2}}{2 k}$

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