Download the app

Questions  

Two springs A and B have force constants kA and KB, respectively, with kA > KB. Both springs are stretched by the same force, then the work done is :

a
same in both cases
b
greater in case of spring A
c
smaller in case of spring A
d
none of the above

detailed solution

Correct option is C

Work done by spring force =12kx2=(kx)22k=F22k

Talk to our academic expert!

+91

Are you a Sri Chaitanya student?


Similar Questions

Two similar springs P and Q have spring constants Kp and KQ such that Kp > KQ. They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs WP and WQ are related as, in case (a) and case (b), respectively.


phone icon
whats app icon