Questions
Two springs A and B (KA = 2KB) are stretched by same suspended weight, The ratio of work done in stretching is :
detailed solution
Correct option is A
work done =12Kx2=(Kx)22K=(mg)22KTalk to our academic expert!
Similar Questions
Two similar springs P and Q have spring constants such that Kp > . They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs are related as, in case (a) and case (b), respectively.
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