First slide

Work done by Diff type of forces

Question

Two springs A and B with spring constant 2K and K are stretched separately by some force F. Then the ratio of work done in stretching A to that in stretching B is

Easy

A

4 : 1
B

1 : 4
C

1 : 2
D

2 : 1

Solution

$W = \frac{1}{2} K x^{2} = \frac{1}{2} K {(\frac{F}{K})}^{2} = \frac{F^{2}}{2 K}$
$∴ \frac{W_{A}}{W_{B}} = \frac{K_{B}}{K_{A}} = \frac{K}{2 K} = \frac{1}{2}$

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