Two springs of force constant $$1000$$ $$N/m$$ & $$2000$$ $$N/m$$ are stretched by same force. The ratio of their respective potential energies is

Question

Infinity Learn · Accepted Answer

potential energy $$PE$$ $$=$$ $$12KX2$$  ; $$K=force$$ constant; x $$=$$ displacement     restoring force $$=F$$ $$=-KX$$                               ⇒$$FK=-X$$ ;  substitute X value in $$PE$$ equation, $$PE$$ $$=12KF2K2$$ $$=12F2K$$ for two springs, $$PE1$$ $$=12F2K1$$  $$PE2$$ $$=12F2K2$$  divide the above two equations, one by the other $$PE1$$ $$PE2=K2K1$$  ; substitute the given vales of $$K1$$,$$K2$$ $$PE1$$ $$PE2==20001000=21$$

Two springs of force constant 1000 N/m & 2000 N/m are stretched by same force. The ratio of their respective potential energies is

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