First slide

Simple hormonic motion

Question

Two springs of force constants 1000 N/m and 2000 N/m are stretched by same force. The ratio of their respective potential energies is

Easy

A

2 : 1
B

1 : 2
C

4 : 1
D

1 : 4

Solution

$P.E. = \frac{1}{2} {Kx}^{2}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App