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Two springs have their force constant as k1 and k2(k1 >k2). When they are stretched by the same force

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a
No work is done in case of both the springs
b
Equal work is done in case of both the springs
c
More work is done in case of second spring
d
More work is done in case of first spring

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detailed solution

Correct option is C

W = F22kIf both springs are stretched by same force then W is directly proportional to 1kAs k1 > k2 therefore W1 < W2i.e., more work is done in case of second spring.


Similar Questions

Two similar springs P and Q have spring constants Kp and KQ such that Kp > KQ. They are stretched first by the same amount (case a), then by the same force (case b). The work done by the springs WP and WQ are related as, in case (a) and case (b), respectively.


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