First slide

Work done by Diff type of forces

Question

Two springs have their force constants as K₁ and K₂(K₁ > K₂). The work done, when both are stretched by the same amount of length, will be :

Easy

A

equal
B

greater for K₁
C

greater for K₂
D

given data is incomplete

Solution

$W_{1} = \frac{1}{2} K_{1} x^{2} W_{2} = \frac{1}{2} K_{2} x^{2}$
$K_{1} > K_{2} \Rightarrow W_{1} > W_{2}$

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