Two springs of spring constants k1 and k2 are joined in series. The effective spring constant of the-combination is given by:
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a
k1k2
b
(k1+k2)2
c
k1+k2
d
k1k2(k1+k2)
answer is D.
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Detailed Solution
Let us consider two springs of spring constants k1 and k2 joined in series as shown in the figure.Under a force F, they will stretch by y1 and y2.So y = y1+y2or Fk = F1k1+F2k2but as springs are massless, so force on them must be the same, i,e., F1 = F2 = FSo, 1k = 1k1+1k2 or k = k1k2k1+k2Aliter: In series combination,1kS = 1k1+1k2 = k2+k1k1k2 ⇒kS = k1k2k1+k2