Two springs of spring constants 1500 N/m and 3000 N/m respectively are stretched with the same force. They will have potential energy in the ratio

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4 : 1

1 : 4

2 : 1

1 : 2

answer is C.

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Detailed Solution

U=F22k⇒U1U2=k2k1 (if force are same)∴U1U2=30001500=21

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