Q.
Two springs of spring constants 1500 N/m and 3000 N/m respectively are stretched with the same force. They will have potential energy in the ratio
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a
4 : 1
b
1 : 4
c
2 : 1
d
1 : 2
answer is C.
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Detailed Solution
U=F22k⇒U1U2=k2k1 (if force are same)∴U1U2=30001500=21
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