Questions
Two springs of spring constants 1500 N/m and 3000 N/m respectively are stretched with the same force. They will have potential energy in the ratio
a
4:1
b
1:4
c
2:1
d
1:2
detailed solution
Correct option is C
Potential energy PE=12kx2 Restoring Force of spring F=-Kx displacement ⇒x=FK Substitute x value in PE, PE=12KFK2 PE=12KF2K2 PE=12F2/K PE1PE2=K2K1 =3000/1500 PE1:PE2=2:1Talk to our academic expert!
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When the displacement is half the amplitude, the ratio of potential energy to the total energy is
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