First slide

Applications of SHM

Question

Two springs with spring constants $K_{1} = 1500 N / m$ and $K_{2} = 3000 N / m$ are stretched by the same force. The ratio of potential energy stored in spring will be

Moderate

A

2 : 1
B

1 : 2
C

4 : 1
D

1 : 4

Solution

$U = \frac{F^{2}}{2 K} \Rightarrow U \propto \frac{1}{K} \Rightarrow \frac{U_{1}}{U_{2}} = \frac{K_{2}}{K_{1}} = 2$

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