First slide

Projection Under uniform Acceleration

Question

Two stones are projected with the same speed but making different angles with the horizontal. Their horizontal ranges are equal. The angle of projection of one is $\frac{π}{3}$ and maximum height reached is 102m. Then the maximum height reached by the other in meter is ____

Easy

A

336
B

224
C

56
D

34

Solution

$θ_{1} = 60^{\circ} θ_{2} = 90^{\circ} - 60^{\circ} = 30^{\circ} ∵ R_{1} = R_{2} 102 = \frac{u^{2}}{2 g} \times \sin 60^{\circ} H^{1} = \frac{u^{2}}{2 g} \times \sin^{2} 30^{\circ} = \frac{u^{2}}{2 g} \times \frac{3}{4}, = \frac{u^{2}}{2 g} \times \frac{1}{4} \Rightarrow H^{1} = 34 m$

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