First slide
Projection Under uniform Acceleration
Question

Two stones are projected with the same speed but making different angles with the horizontal. Their ranges are equal. If the angle of projection of one is π/3 and its maximum height is y1, then the maximum height of the other will be

Easy
Solution

Here speeds of projection and ranges are same and hence angles of projections are π3 and π2π3=π6

Now        

y2y1=u2sin2θ22g×2gu2sin2θ1=sin2θ2sin2θ1=sin2(π/6)sin2(π/3)=13 or y2=y13

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