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Q.

Two stones are projected with the same speed but making different angles with the horizontal. Their ranges are equal. If the angle of projection of one is π/3 and its maximum height is y1, then the maximum height of the other will be

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a

3y1

b

2y1

c

y1/2

d

y1/3

answer is D.

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Detailed Solution

Here speeds of projection and ranges are same and hence angles of projections are π3 and π2−π3=π6Now y2y1=u2sin2⁡θ22g×2gu2sin2⁡θ1=sin2⁡θ2sin2⁡θ1=sin2⁡(π/6)sin2⁡(π/3)=13 or y2=y13

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