First slide

Projection Under uniform Acceleration

Question

Two stones are projected with the same speed but making different angles with the horizontal. Their ranges are equal. If the angle of projection of one is $π$ /3 and its maximum height is h₁ then the maximum height of the other will be

Easy

A

3h₁
B

2h₁
C

h1/2
D

h1/3

Solution

$\frac{h_{2}}{h_{1}} = \frac{u^{2} \sin^{2} θ_{2}}{2 g} \times \frac{2 g}{u^{2} \sin^{2} θ_{1}} = \frac{\sin^{2} θ_{2}}{\sin^{2} θ_{1}} = \frac{\sin^{2} π / 6}{\sin^{2} π / 3} = \frac{1}{3} h_{2} = \frac{h_{1}}{3}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App