Two stones are projected with same speed so as to reach the same distance from the point of projection on a horizontal
surface. The maximum height reached by one exceeds the other by an amount equal to half the sum of the
height attained by them. Then, angle of projection of the stone which attains smaller height is

Question

Infinity Learn · Accepted Answer

It is given that,   $$H1-H2=H1+H22$$ or $$H1=3H2$$∴  $$u2sin2$$θ$$2g=3u2sin290$$°$$-$$θ$$2g$$⇒  $$tan2$$θ$$=3$$∴  $$tan$$θ$$=3$$   or θ$$=60$$°Therefore, the other angle is  $$90$$°$$-$$θ or $$30$$°

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