Two stones are projected with same speed so as to reach the same distance from the point of projection on a horizontalsurface. The maximum height reached by one exceeds the other by an amount equal to half the sum of theheight attained by them. Then, angle of projection of the stone which attains smaller height is
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a
450
b
600
c
300
d
tan-1(3/4)
answer is C.
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Detailed Solution
It is given that, H1-H2=H1+H22 or H1=3H2∴ u2sin2θ2g=3u2sin290°-θ2g⇒ tan2θ=3∴ tanθ=3 or θ=60°Therefore, the other angle is 90°-θ or 30°