Two stones are thrown up simultaneously with initial speeds of $u_{1}$ and $u_{2} (u_{2} > u_{1}) .$ They hit the ground after $6 s$ and $10 s$ respectively. Which graph in figure correctly represents the time variation of $Δ x = (x_{2} - x_{1})$ , the relative position of the second stone with respect to the first upto $t = 10 s$ ?
Assume that the stones do not rebound after hitting the ground.

Question

Two stones are thrown up simultaneously with initial speeds of $u_{1}$ and $u_{2} (u_{2} > u_{1}) .$ They hit the ground after $6 s$ and $10 s$ respectively. Which graph in figure correctly represents the time variation of $Δ x = (x_{2} - x_{1})$ , the relative position of the second stone with respect to the first upto $t = 10 s$ ?

Assume that the stones do not rebound after hitting the ground.

Infinity Learn · Accepted Answer

Initially, relative acceleration between them is zero, so distance between them will increase linearly Later when  stone $$1$$ strikes the ground, relative acceleration is g, so distance will decrease parabolically.

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