Two stones of masses m and 2 m are whirled in horizontal circles, the heavier one in a radius r2 and the lighter one in radius r. The tangential speed of lighter stone is n times that of the value of heavier stone when they experience same centripetal forces. The value of n is
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a
4
b
1
c
2
d
3
answer is C.
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Detailed Solution
Let ν be tangential speed of heavier stone. Then, Centripetal force experienced by lighter stone isFclighter =m(nv)2rand that of heavier stone is Fcheavier =2mv2(r/2) But Fclighter =Fcheavier (given) ∴ m(nv)2r=2mv2(r/2)n2mv2r=4mv2rn2=4 or n=2