Two straight parallel wires, both carrying 10 A current in the same direction, attract each other with a force of current 1 × 10−3N. If both currents are doubled, the force of attraction will be

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1 × 10−3N

2 × 10−3N

4 × 10−3N

0.25 × 10−3N

answer is C.

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Detailed Solution

F=μ04π 2i1i2a × l=10−3 NWhen current in both the wires is doubled, thenF'=μ04π 22i1 ×2i2a × l=4 ×10−3 N

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