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Q.

Two straight parallel wires, both carrying 10 A current in the same direction, attract each other with a force of current 1 × 10−3N. If both currents are doubled, the force of attraction will be

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a

1 × 10−3N

b

2 × 10−3N

c

4 × 10−3N

d

0.25 × 10−3N

answer is C.

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Detailed Solution

F=μ04π  2i1i2a  ×  l=10−3 NWhen current in both the wires is doubled, thenF'=μ04π  22i1 ×2i2a  ×  l=4 ×10−3 N
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