Two strings X and Y of a sitar produce a beat frequency $$4$$ Hz. When the tension of the string Y is slightly increased the beat frequency is found to be $$2$$ Hz. If the frequency of X is $$300$$ Hz, then the original frequency of Y was

Question

Infinity Learn · Accepted Answer

$$nx=300Hz$$,  $$ny=$$?x $$=$$ beat frequency $$=$$ $$4$$ Hz, which is decreasing $$(4$$→$$2)after$$ increasing the tension of the string y. Also  tension of wire y increasing so ny​↑  $$($$∵ n∝$$T)Hence$$ nx−ny​↓$$=x$$​↓        →      Correct              ny​↑−$$nx=x$$​↓       →        Wrong ⇒$$ny=nx$$−$$x=300$$−$$4=296Hz$$

Two strings X and Y of a sitar produce a beat frequency 4 Hz. When the tension of the string Y is slightly increased the beat frequency is found to be 2 Hz. If the frequency of X is 300 Hz, then the original frequency of Y was

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