Two syringes of different cross section (without needle) filled with water are connected with a tightly fitted rubber tube filled with water. Diameters of the smaller piston and larger piston are 1 cm and 3 cm respectively. If a force of 10 N is applied to the smaller piston then the force exerted on the larger piston is
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a
30 N
b
60 N
c
90 N
d
100 N
answer is C.
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Detailed Solution
Since pressure is transmitted undiminished through out the waterF1A1 = F2A2where F1 and F2 are the forces on the surface and on the larger pistons respectively and A1 and A2 are the respective areas.F2 = A2A1F1 = π(D22)2π(D12)2F1=(D2D1)2F1 = (3×10-2m)2(1×10-2m)2×10N = 90 N