Two tanks A and B contain water at 30°C and 80°C respectively. The amount of water that must be taken from A and B to prepare 40 kg of water at 50°C :

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24 kg, 16 kg

16 kg, 24 kg

20 kg, 20 kg

30 kg, 10 kg

answer is A.

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Detailed Solution

Heat lost = Heat gained ⇒ mA×1×(50-30)=mB×1×(80-50)⇒mAmB=32 Also mA+mB=40 So, mA=24 kg and mB=16 kg

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