First slide

Specific heat

Question

Two tanks A and B contain water at 30°C and 80°C respectively. The amount of water that must be taken from A and B to prepare 40 kg of water at 50°C :

Moderate

A

24 kg, 16 kg
B

16 kg, 24 kg
C

20 kg, 20 kg
D

30 kg, 10 kg

Solution

Heat lost = Heat gained
$\Rightarrow m_{A} \times 1 \times (50 - 30) = m_{B} \times 1 \times (80 - 50) \Rightarrow \frac{m_{A}}{m_{B}} = \frac{3}{2} Also m_{A} + m_{B} = 40 So, m_{A} = 24 kg and m_{B} = 16 kg$

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