Two thin metal strips, one of brass and the other of iron are fastened together parallel to each other. Thickness of each strip is $$1$$ mm. If the strips are of equal length at $$0$$°C . The inner radius of the arc formed by the bimetallic strip when heated to $$80$$°C is (Coefficient$$ of linear expansion of brass $$=$$ $$19$$×$$10$$–$$6/0C$$ & of iron $$=$$ $$12$$ × $$10$$–$$6/0C).

Question

Infinity Learn · Accepted Answer

d $$=$$ $$t1$$ $$+$$ $$t2$$ $$=$$ $$1$$ $$+$$ $$1$$ $$=$$ $$2mm$$ $$=$$ $$2$$ x $$10-3m$$θ$$1$$ $$=$$ $$00C$$, θ$$2$$ $$=$$ $$800C$$, α$$1$$ $$=$$ $$19$$ x $$10-6$$, α$$2$$ $$=$$ $$12$$ x $$10-6Inner$$  radius of curvature of bimetallic strip

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