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Two thin rings having masses m1 and m2, each of radius R, are coaxially placed at a distance R. Then the work done in moving a particle of mass m from the centre of one ring to that of the other is

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a
Zero
b
Gmm1−m2  2 −12R
c
2Gmm1+m2R
d
Gm2m1+m2R

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detailed solution

Correct option is B

V1=−Gm1R − Gm22R V2=−Gm2R − Gm12R ∴     ΔV=V2−V1=Gm1−m2  1R−12R Hence, W=m.ΔV=G.mm1−m2  2 −12 R


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