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Q.

Two thin wire rings each having a radius R are placed at  a distance d apart with their axes coinciding. The charges on the two rings are +q and -q. The potential difference between the centres of the two rings is

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a

Zero

b

Q4πε0 1R−1R2+d2

c

QR/4πε0d2

d

Q2πε01R−1R2+d2

answer is D.

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Detailed Solution

Potential at the centre of rings are VO1=k.qR+k(−q)R2+d2, VO2=k(−q)R+kqR2+d2⇒VO1−VO2=2kq 1R−1R2+d2=q2πε01R−1R2+d2
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