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Questions  

Two thin wire rings each having a radius R are placed at a distance d apart with their axes coinciding. The charges on the two rings are + q and - q. The potential difference between the centres of the two rings is :

a
qR4πε0d2
b
q2πε01R-1R2+d2
c
Zero
d
q4πε01R-1R2+d2

detailed solution

Correct option is B

∆V=kqR+k(-q)R2+d2-k(-q)R+kqR2+d2 =2kqR-2kqR2+d2=q2πε01R-1R2+d2

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