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Q.

Two thin wire rings each having a radius R are placed at a distance d apart with their axes coinciding. The charges on the two rings are +q and –q. The potential difference between the centres of the two rings is

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a

q2π∈0[1R1R2+d2]

b

qR4π∈0d2

c

q4π∈0[1R−1R2+d2]

d

Zero

answer is A.

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Detailed Solution

At (1) using, potential (v1)=Vself+Vdue to(2)⇒V1=14πε0[qR−qR2+d2]At (2) using potential (V2)=Vself+Vdueto(1)⇒V2=14πε0[−qR+qR2+d2]ΔV=V1−V2=14πε0[qR+qR−qR2+d2−qR2+d2]=12πε0[qR−qR2+d2]
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