Two towns A and B are connected by a regular bus service with a bus leaving in either direction every T minutes. A man cycling with a speed $$20$$ $$km/hr$$ in the direction A to B notices that a bus goes past him every $$18$$ minutes in the direction of his motion and every $$6$$ min in the opposite direction. Assume the buses ply with constant speed V on the road.

Question

Infinity Learn · Accepted Answer

⇒VTV−$$20=18---(1)$$⇒$$VTV+20=6---(2)1$$÷$$2$$ we get ​VTV−$$20VTV+20=186$$​Solving  we get V $$=$$ $$40$$ $$km/hrsubstituting$$ in (1) we get ⇒T $$=$$ $$9$$ min

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