Two towns A and B are connected by a regular bus service with a bus leaving in either direction every T minutes. A man cycling with a speed 20 km/hr in the direction A to B notices that a bus goes past him every 18 minutes in the direction of his motion and every 6 min in the opposite direction. Assume the buses ply with constant speed V on the road.

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T = 6 min

T = 9 min

V= 40 km/hr

V = 60 km/hr

answer is B.

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Detailed Solution

⇒VTV−20=18---(1)⇒VTV+20=6---(2)1÷2 we get VTV−20VTV+20=186Solving we get V = 40 km/hrsubstituting in (1) we get ⇒T = 9 min

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