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Two tubes of radii r1 and r2 , and lengths l1 and l2 , respectively, are connected in series and a liquid flows through each of them in stream line conditions. P1 and P2 are pressure differences across the two tubes. If P2 is 4P1 and l2 is l14 , then the radius r2 will be equal to:

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a

r1

b

2r1

c

4r1

d

r12

answer is D.

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Detailed Solution

Q1=Q2 ∵V=Q=πPr48ηl ⇒P1r14l1=P2r24l2 ⇒P1r14l1=4P1.r24l1/4 ⇒r2=r12

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Two tubes of radii r1 and r2 , and lengths l1 and l2 , respectively, are connected in series and a liquid flows through each of them in stream line conditions. P1 and P2 are pressure differences across the two tubes. If P2 is 4P1 and l2 is l14 , then the radius r2 will be equal to: