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Two tuning forks A and B vibrating simultaneously produce 5 beats. Frequency of B is 512. It is seen that if one arm of A is filed, then the number of beats increases. Frequency of A will be

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a
502
b
507
c
517
d
522

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detailed solution

Correct option is C

After filling frequency increases, so  nA decreases (↓). Also it is given that beat frequency increases (i.e., x ↑)  Hence nA↓ – nB  = x↑        ... (i)       →        Correct           nB  – nA↑ = x↑        ... (ii)       →        Wrong⇒ nA = nB + x = 512 + 5 = 517 Hz.


Similar Questions

A metal wire of diameter 1.5 mm is held on two knife edges separated by a distance 50 cm the tension in the wire is 100 N the wire vibrating with its fundamental frequency and vibrating tuning fork together produces 5 beats per second. The tension in the wire is then reduced to 81 N, when the two are excited, beats are heard at the same rate. Calculate frequency of the fork.


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