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Q.

Two uniform rods A and B of lengths 5m and 2 m are placed end to end. If their linear densities are 4 kg/m and1kg/m, the position of their centre of mass from their interface is

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a

2411m on the side of heavier rod

b

1124mon the side of lighter rod

c

209m on the side of heavier rod

d

159mon the side of lighter rod.

answer is A.

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Detailed Solution

m1=5×4=20kg, m2=2×1=2kg,         x1=52=2.5m, x2=22=1mXCM=−20×2.5+2×122=−50+222=−4822⇒−2411
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