First slide

Moment of intertia

Question

Two uniform rods of mass ‘m’ and length ‘l’ form a cross, moment of inertia of cross about an axis parallel to CD passing through A is

Moderate

A

$\frac{7}{12} m l^{2}$
B

$\frac{m l^{2}}{6}$
C

$\frac{2 m l^{2}}{3}$
D

$\frac{5 m l^{2}}{12}$

Solution

moment of inertia of rod AB about an axis passing through A and parallel to CD $\frac{m l^{2}}{3}$ and that for rod CD is $\frac{m l^{2}}{4}$ so total moment of inertia is $\frac{7 m l^{2}}{12}$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App