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Two uniform strings A and B made of steel are made to vibrate under the same tension. if the first overtone of A is equal to the second overtone of B and if the radius of A is twice that of B, the ratio of the lengths of the strings is 

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d
1 : 6

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detailed solution

Correct option is B

First overtone of string A = Second overtone of string B.⇒Second harmonic of  A = Third harmonic of B⇒n2=n3⇒2(n1)A=3(n1)B  (∵n1=12lTπr2ρ)⇒2 12lArATπρ=3 12lBrBTπρ lAlB=23rBrA⇒lAlB=23×rB(2rB)=13


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