Questions
Two uniform thin identical rods. AB and CD each of mass M and length I are joined so as to form a cross as shown in fig. The moment of inertia of the cross
about the bisector line EF is
detailed solution
Correct option is C
The line EF makes an angle of 450 with each rod .Therefore I = I1 +I2 =( 112ML2sin2 450 )×2=112ML2Talk to our academic expert!
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A rectangular loop has mass M and sides a and b. An axis passes tlrrough the centre C of the loop and is parallel to side a (lie in the plane of the loop). Then the radius of gyration of the loop, for the axis is
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