Two uniform wires A and B are of the same metal and have equal masses. The radius of wire A is twice that of wire B. The total resistance of A and B when connected in parallel is
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a
4 Ω when the resistance of wire A is 4.25 Ω
b
5 Ω when the resistance of wire A is 4.25 Ω
c
4 Ω when the resistance of wire B is 4.25 Ω
d
4 Ω when the resistance of wire B is 4.20 Ω
answer is A.
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Detailed Solution
RARB=rBrA4 ⇒ RARB=124 =116 ⇒ RB=16RAWhen RA and RB are connected in parallel, then equivalent resistance Req=RARBRA+RB=1617 RAIf RA=4.25 Ω then Req=4 Ω