Two vectors a→ and b→ of different magnitude are found to have a resultant of magnitude R. On reversing one of them, the resultant is again found to have the same magnitude R. Then the angle between the vectors a→ and b→ must be
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a
900
b
1200
c
600
d
450
answer is A.
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Detailed Solution
Given a→ + b→=R, on reversing the second vector a→ − b→=R . Thus a→ + b→=a→−b→. If θ is angle between a→ and b→, then a2+b2+2abcosθ=a2+b2−2abcosθ.Solve for θ