Two vectors A and B have magnitudes 6 units and 8 units, respectively. Find |A-B| if the angle between two vectors is 90°

Magnitude of vector A=6 Units. Magnitude of vector B=8 units.Now resultant =|A-B| will be equal to A2+B2-2ABcos(θ)when angle between them is 90 degree:Then |A-B|=62+82-(2)(6)(8)cos(90)=100( since cos(90)=0)= 10 units