Questions
Two vessels each of volume ‘V’ contains ideal gases at pressure P, temperature T. They are connected by a narrow pipe without changing temperature of 1st gas . Temperature of 2nd vessel is increased to 2T. Then , common pressure of gases is
detailed solution
Correct option is D
P2=2P1T1T1+T2 ⇒Pcommon=4P3Talk to our academic expert!
Similar Questions
For one-mole ideal gas, a process follows the relation where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?
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