Two vessels each of volume ‘V’ contains ideal gases at pressure P, temperature T. They are connected by a narrow pipe without changing temperature of 1st gas . Temperature of 2nd vessel is increased to 2T. Then , common pressure of gases is

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3P2

4P3

answer is D.

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Detailed Solution

P2=2P1T1T1+T2 ⇒Pcommon=4P3

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