Questions
Two vessels separately contain two ideal gases A and B at the same temperature, the pressure of A being twice that of B. Under such conditions, the density of A is found to be 1.5 times the density of B. The ratio of molecular weight of A and B is
detailed solution
Correct option is D
According to an ideal gas equation, the molecular weight of an ideal gas isM=ρRTP as P=ρRTMwhere P, T and ρ are the pressure, temperature and density of the gas respectively and R is the universal gas constant.∴ The molecular weight of A isMA=ρARTAPAand that of B isMB=ρBRTBPB Hence, their corresponding ratio is MAMB=ρAρBTATBPBPA Here, ρAρB=1.5=32,TATB=1 and PAPB=2∴ MAMB=32(1)12=34Similar Questions
For one-mole ideal gas, a process follows the relation where P0 and V0 are constants. If the volume the gas changes from V0 to 2V0. What is the change in temperature?
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