Two vessels separately contain two ideal gases A and B at the same temperature, the pressure of A being twice that of B. Under such conditions, the density of A is found to be $$1.5$$ times the density of B. The ratio of molecular weight of A and B is

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According to an ideal gas equation, the molecular weight of an ideal gas $$isM=$$ρRTP   as $$P=$$ρRTMwhere P, T and ρ are the pressure, temperature and density of the gas respectively and  R  is the universal gas constant.∴ The molecular weight of A $$isMA=$$ρARTAPAand that of B $$isMB=$$ρBRTBPB Hence, their corresponding ratio is $$MAMB=$$ρAρBTATBPBPA Here, ρAρ$$B=1.5=32$$,$$TATB=1$$ and $$PAPB=2$$∴  $$MAMB=32(1)12=34$$

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