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Q.

Two vibrating strings of the same material but length L and 2L have radii 2r and r respectively . They are stretched under the same tension. Both strings vibrates in their fundamental nodes. The one of length ‘L’ with frequency  n1 and other with frequency n2 .  The ratio of  n1/n2 is given

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a

2

b

4

c

8

d

1

answer is D.

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Detailed Solution

Fundamental frequency for first string  : n1=12lT4πr2ρ                                                                   ⇒ n1=14lTπr2ρ  →  1   and  Fundamental frequency for second string  : n2=12(2l)Tπr2ρ    → 2  Divide i/ii                        n1n2=1
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