Two vibrating strings of the same material but length L and 2L have radii 2r and r respectively . They are stretched under the same tension. Both strings vibrates in their fundamental nodes. The one of length ‘L’ with frequency n1 and other with frequency n2 . The ratio of n1/n2 is given
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a
2
b
4
c
8
d
1
answer is D.
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Detailed Solution
Fundamental frequency for first string : n1=12lT4πr2ρ ⇒ n1=14lTπr2ρ → 1 and Fundamental frequency for second string : n2=12(2l)Tπr2ρ → 2 Divide i/ii n1n2=1